Use the following information to solve the problem using a Punnett square: Assume that the dominant "A" allele encodes normal pigmentation and the recessive "a" allele encodes albinism. An individual with the genotype aa has children with an individual of the genotype Aa. What is the percent chance that they would have children with albinism

50% or 1/2

Explanation:

chance that they would have children with albinism is 50.

A allele encodes normal pigmentation.

a allele encodes albinism.

An aa individual has children with an Aa individual

aa   x   Aa

Offspring = Aa, aa, Aa, and aa = 2 Aa + 2 aa (See the attached Punnet's square)

Based on the assumption that the A allele is dominant over the a allele, Aa individuals will have normal pigmentation while aa individuals will be albinos.

Hence,

Percentage of their children that will have normal pigmentation (Aa) = 50% or 1/2.

Percentage of their children that will be albino (aa)= 50% or 1/2.

bc blah

explanation:

bc blah

they absorb it i think

not sure

you