In peas, the allele for tall (T) is dominant over short (t), and the unlinked gene for seed color has the allele for yellow seeds (G) dominant over green seeds (g). What is the predicted phenotypic ratio for offspring from this cross: Ttgg x ttGga.3 tall, yellow: 3 tall, green: 1 short, yellow: 1 short, greenb.3 tall, yellow: 1 tall, green: 3 short, yellow: 1 short, greenc.9 tall, yellow: 3 tall, green: 3 short, yellow: 1 short, greend.1 tall, yellow: 1 tall, green: 1 short, yellow: 1 short, greene.1 tall, yellow: 1 tall, green

d 1 tall, yellow: 1 tall, green: 1 short, yellow: 1 short, greene.1 tall, yellow: 1 tall, green

Explanation:

The predicted phenotype will be 1 tall, yellow: 1 tall, green: 1 short, yellow: 1 short, greene.1 tall, yellow: 1 tall, green

The two genes are unlinked. This means that they are independent of each other. In other words, they are independently inherited.

Ttgg was crossed with ttGg

Ttgg   x   ttGg

Offpsring

4 TtGg    tall and yellow

4 ttGg     short and yellow

4 Ttgg     tall and green

4 ttgg      short and green

Hence, the phenotypic ratio is 1:1:1:1.

The correct option is d.

You can view the attached image for the Punnet's square analysis.

chromosomes carry the genetic information for organisms. also, chromatin is the thread like dna which is located in the nucleus of an organism.

the overall balanced equation

6co2 + 6h2o > c6h12o6 + 6o2

sunlight energy

where: co2 = carbon dioxide

h2o = water

light energy is required

c6h12o6 = glucose

o2 = oxygen