One side (one polymer of nucleotides) of the DNA molecule is said to be complementary to the other
side of the molecule. Which of these best formulates how the structure of DNA pairs perfectly to the
process of DNA replication?
a) During DNA replication, transfer RNA molecules bring amino acids to the exposed gene.
b) During DNA replication, the molecule splits at the peptide bonds, and amino acids are added to
the new side of the ladder.
c) During DNA replication, the molecule splits at the weak hydrogen bonds, and each side provides
a template for the new side of the ladder.
d) During DNA replication, the enzyme zipperase breaks the weak bonds between the ladder and
complementary lipid molecules are shuttled to the exposed nucleotides,

an individual’s sex (i.e., whether they are a male or female) is determined by the sex chromosomes. most people have two sex chromosomes, one that is inherited from their mother and one that is inherited from their father. typically, females have two x chromosomes (xx) and males have one x chromosome and one y chromosome (xy). conditions caused by changes (“mutations”) in genes located on the x chromosome are considered x-linked.

x-linked recessive inheritance

most x-linked conditions are recessive. this means that in a person with two x chromosomes (most females), both copies of a gene (i.e., one on each x chromosome) must have a change or mutation whereas in a person with one x chromosome (most males), only one copy of a gene must have a mutation. a female with a mutation in one copy of a gene on the x chromosome is said to be a “carrier” for an x-linked condition. a male with a mutation in a gene on the x chromosome is typically affected with the condition. because females have two copies of the x chromosome and males have only one x chromosome, x-linked recessive diseases are more common among males than females. however, x-linked recessive diseases can occur in both males and females.

for x-linked recessive disorders, an unaffected carrier mother who has a mutation in a gene on the x chromosome can transmit either the x chromosome with this mutation or a “normal” x chromosome to her children. if the father is unaffected, none of her daughters will be affected and all of her daughters will be unaffected—since they will inherit at least one normal x chromosome from their father. however, each daughter will have a 50% chance of being an unaffected carrier like her mother and a 50% chance of both x chromosomes being normal.

multiply it by 5 in order for you to understand i cant give an exact answer.