A heterozygous right handed mom and a homozygous left handed dad (recessive) mate. What percent of children are expected to be left handed?

50% chance will left handed.  

Explanation:

Right handed = dominant (R)

Left handed = recessive (r)

Heterozygous right handed mom = Rr

Homozygous left handed dad = rr

According to punnett's square:

Rr    x     rr

=2/4 Heterozygous (Rr)

= 2/4 homozygous recessive (rr)

So, there will be 50 % or 2/4 chance of left handed children.

answer; ///(statins)/aka as hmg coa

answer: 20 percent

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