Apopulation of mice has black or brown hair. the gene for black hair color (b) is dominant over brown (b). if 16% of the mice are homozygous black and 24% are heterozygous black, what would be the frequency of each allele? . (p + q = 1, p2 + 2pq + q2 = 1). is it (a. p=0.65, q=0.35 (b. p=0.25, q=0.75 (c. p=0.4, q=0.6

Frequency of black allele is

Frequency of brown allele is

Explanation:

As per Hardy-Weinberg equation,

Frequency of the homozygous genotype is represented by AA and aa

Frequency of the heterozygous genotype is represented by Aa

In the  Hardy-Weinberg mathematical equation

Frequency of AA is represented by

Frequency of AA is represented by

Frequency of AA is represented by

And the mathematical equation is as follows -

Substituting the given values in above equation we get

Also,  sum of the allele frequencies for all the alleles at the locus is equal to  1 which means

Frequency of black allele is

Frequency of brown allele is

lipid

explanation:

if the hares very faster than they are now, and thus the lynx's hunting success rate drops because it will be harder to catch them, the rate that will change will be the pray-rate. the pray-rate will change because more hares will be able to survive, thus more individuals for reproduction, so the end result will be increasing population of hares.

the predator-rate will remain pretty much the same because there will be more than enough pray, but the hunting success rate is stagnant.