In a proton accelerator used in elementary particle physics experiments, the trajectories of protons are controlled by bending magnets that produce a magnetic field of 4.40 T. You may want to review (Pages 997 - 1000) . For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Storing energy in an inductor.

77.0J

Explanation:

The magnetic field is given as 4.40T

Since the volume is not given, we assume that the volume is 10.0cm³

We need to find the magnetic field energy in this volume.

The energy density is:

u = B²/2u•

u• is given as 4π × 10^-7 T.m/A

Using this formula we substitute

u = B²/2u• = (4.40 T)²/ 2(4π × 10^-7 T.m/A) = 7.704 × 10^6 J/m³

The energy is equal to the energy density multiply by the volume. You get;

U= uV = (7.704 × 10^6 J/m³) × (10.0 × 10^6m³) = 77.0J

the actual answer was 160934