You are interested in cloning a gene from the B. sanfranciscus genome, so you design PCR primers that should amplify a 1 kilobase pair (kbp) PCR product that contains the gene of interest. After amplification, you will see if the PCR was successful by loading the reaction onto an agarose gel and performing electrophoresis to see if a product of the expected size was generated. To visualize the DNA, you will stain the gel with a fluorescent dye called Sybr Green, which fluoresces when it binds to DNA. The sensitivity of Sybr Green-stained DNA is 1 nanogram (i. e. - there must be at least 1 ng of DNA in the band in the gel to emit a detectable amount of light) If your PCR reaction initially contained 10 B. sanfranciscus genomes, after how many cycles of PCR will there be a detectable amount of amplified product? You can assume: a) there is 1 copy of the gene per genome, b) the PCR occurs with perfect efficiency and therefore the amount of product doubles after each cycle, and, c) that the molecular weight of a 1 kbp molecule of DNA is 6.5 x 105 Daltons. Express your answer in the number of complete (not fractional) cycles and show your work.

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Explanation:

So we identified that 1 ng = 1.66 x 1015 Dalton.

Now by the question, here we have 10 genomes, in which it comprise our gene of interest of 1kb. 1kbp molecule of DNA is 6.5 x 105 Dalton. So the overall weight of the initial volume of DNA is 6.5x 105 x 10. = 6.5 x 106 Dalton.

So, we can obviously understand that in order to visualize we have to boost and enhance our volume about 109 times.

So here we can identify that if initial product is " i" after n number of cycle then finishing product would be f = i x 2n . after that we get

6.5 x 1015 = 6.5 x 106 x 2n

109 = 2n

If you calculate it this way you are going to get something like 29.789. Cycle can not be in fraction so we will have to perform 30 cycle in order to visualize the band.

If you solve this you will get 29.789 something. Cycle can't be in fraction so we have to perform 30 cycle in order to visualize the band.

Explanation:

So we know that 1 ng = 1.66 x 1015 Dalton.

Here we have 10 genomes, which contains our gene of interest of 1kb. 1kbp molecule of DNA is 6.5 x 105 Dalton. So total weight of initial volume of DNA is 6.5x 10^5 x 10. = 6.5 x 10^6 Dalton.

So , we clearly understand in order to visualize we have to increase our volume about 109 times.

So here we know if initial product is " i" after n number of cycle final product would be f = i x 2^n . Then we get

6.5 x 10^15 = 6.5 x 10^6 x 2^n

10^9 = 2^n

an active site is a region that is present on an enzyme where the reactants or the substrate molecules we can say bind and experience a chemical reaction. the substrate is basically a reactant whose concentration is changing and that is converting into a product after binding at the active site of an enzyme

answer: blah

explanation:

bc blah