Suppose 64% of a remote mountain village can taste phenylthiocarbamide (PTC) and must, therefore, have at least one copy of the dominant PTC taster allele. If this population conforms to Hardy-Weinberg expectations for this gene, what percentage of the population must be heterozygous for this trait?

The correct answer is 48 percent.

Explanation:

Let the dominant allele be signified by letter T and the recessive allele be signified by letter t.

On the basis of Hardy-Weinberg equation, the frequency of T is denoted by p and the frequency of t by q. Therefore, p+q = 1.

p^2 signifies the frequency of TT, 2pq the frequency of Tt and q^2 the frequency of tt, which is denoted by the equation:

p^2 + 2pq + q^2 = 1

Based on the given information, 64 percent of the population are tasters, thus, 36 percent would be the non-tasters, and would exhibit the homozygous recessive genotype, that is, tt.

Thus, the frequency of tt will be 0.36, that is, q^2 will be 0.36 or q = 0.6.

p+q = 1, p = 1-q and so p = 1-0.6, p = 0.4

The frequency of Tt is 2pq = 2*0.6*0.4 = 0.48.

Hence, 48 percent of the population would be the heterozygous for this trait.

explanation:

the universal gravitation equation. since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. if the mass of one of the objects is doubled, then the force of gravity between them is doubled.

i'm guessing this is from edg enuity so the answers would be, from top to bottom,

theodor schwann

matthias schleiden

robert hooke

rudolph virchow

anton van leeuwenhoek