Cystic fibrosis is an autosomal recessive disorder. In one population, the frequency of affected individuals (A 2 A 2) is 0.0004. Assuming that this population is under Hardy-Weinberg equilibrium, calculate all allele frequencies and genotype frequencies. Enter your numerical answers in the boxes below. Express each answer to four decimal places.

Hardy Weinberg Equilibrium

Explanation:

                 =frequency of recessive allele

                 =frequency of dominant genotype

                 =frequency of recessive genotype

                 =frequency of heterozygous genotype

here,affected individuals means the one's having Cystic Fibrosis and since it is recessive disease so we can write frequency of recessive genotype as:     =0.0004

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