Which of the following conversions take place in a metabolic situation that require much more NADPH than ribose 5-phosphate, as well as complete oxidation of glucose 6-phosphate to CO2? [The arrows represent one or more enzymatic steps]A. Glucose 6-phosphate —> —> ribulose 5-phosphateB. Fructose 6-phosphate + glyceraldehydes 3-phosphate —> —> ribose 5-phosphateC. Ribose 5-phosphate —> —> fructose 6-phosphate + glyceraldehydes 3-phosphate D. Glyceraldehydes 3-phosphate —> —> pyruvateE. Fructose 6-phosphate —> —> glucose 6-phosphate

Ribose 5-phosphate —> —> fructose 6-phosphate + glyceraldehydes 3-phosphate

Explanation:

The non oxidative phase or the reversible phase of the hexose monophosphate shunt pathway is important for the the generation of the NADPH molecule and ribulose 5 phosphate.

The ribulose 5 phosphate is used by the cells for the synthesis of nucleotides. Ribulose 5 phosphate is converted into the  fructose 6-phosphate by translketolase and glyceraldehyde 3 phosphate by transaldolase. These steps require more energy than the other steps.

Thus, the correct answer is option (C).

not sure but try c two haploid cells

explanation: