A plant with green pods is crossed with a plant with yellow pods. Draw a Punnett square to predict the outcome of
this cross. List the possible genotypes and their phenotypes. You may need to draw more than one punnet square.
(Note: Round is dominant to wrinkled).

for green, dominant:  

        phenotype:                        4 green ; 0 yellow

       ∴ all are genotypically heterozygous, and green

       phenotype:                        2 green; 2 yellow

      ∴ all are genotypically heterozygous, 2 are green and 2 yellow

for yellow, dominant:  

       phenotype:                    4 yellow; 0 green

      ∴ all are genotypically heterozygous, and yellow

       phenotype:                     2 yellow;     2 green

      ∴ all are genotypically heterozygous, 2 are green and 2 yellow

Explanation:

Punnett squares are a diagrammatic way of deciding the characteristics of hybrid offspring created by crosses in genetic breeding. Parental genotypes and phenotypes are widely recognized, and all usually obey normal Mendelian ratios and inheritance.

Mendelian genetics focuses on the origin or heritability of characteristics. Such traits are packed into one's own gamete, acquired by themselves, and sometimes display superiority, where one's impact can mask those of another trait.

These are called the Law of Segregation, Independent assortment and Dominance respectively.

For this cross...

Assuming Green= dominant

Parent generation or P generation:

gametes: G → pod color green dominant (G), yellow recessive (y)

Assuming heterozygousity

P generation:                          Gy× yy

                                        green  × yellow

F1 generation:                         Gy× yy         ...(from punnet square)

phenotype:                        2 green; 2 yellow

∴ all are genotypically heterozygous, 2 are green and 2 yellow

Assuming true breeding parents (homozygous)

P generation:                       GG × yy

                                        green  × yellow

F1 generation:                         Gy    ×  Gy           ...(from punnet square)

phenotype:                        4 green ; 0 yellow

∴ all are genotypically heterozygous, and green

Assuming yellow= dominant

Parent generation or P generation:

gametes: Y → pod color y dominant (Y), green recessive (g)

Assuming true breeding parents(homozygous)

P generation:                       YY × gg

                                        Yellow  × green

F1 generation:                         Yg   ×  Yg        ...(from punnet square)

phenotype:                    4 yellow; 0 green

∴ all are genotypically heterozygous, and green

Assuming heterozygousity

P generation:                          Yg× gg

                                          yellow ; green  

F1 generation:                         Yg × gg       ...(from punnet square)

phenotype:                     2 yellow;     2 green

∴ all are genotypically heterozygous, 2 are green and 2 yellow

Each punnet cross is attached in order below

check for the pregnancy rating of drug. if its class c or d see if other alternatives