Assume that the mother's genotype is AZ/az, and the father's genotype is Az/aZ, and the recombination rate is 10%. What are the probabilities of an 'az' gamete from each parent? Group of answer choices .5 from mom, 0 from dad .4 from mom, .1 from dad .45 from mom, .05 from dad .1 from mom, .05 from dad

.45 from mom, .05 from dad

Explanation:

Given that:

the mother's genotype is AZ/az

i.e AZ = 50%

az = 50%     (parental)

But  we  were also told that the recombination rate is 10% which will like wise affect the mother's genotype

So 100% -10% = 90 % of the mother's genotype

We have a new genotype

AZ = 45%

az = 45% (parental)

Therefore the probability of az gamete from the mother =

= 0.45

Similarly; the genotype of the father is:  Az/aZ

This is an heterozygous father who is diploid hence, there is a remarkable presence of two copies of each autosomal chromosome.

Az is the allele of the genes in one chromosomes and aZ is the allele of the genes in the other.

The gametes of this self cross are: Aa, AZ, az, zZ

Therefore; the recombinants are:

AZ

az

Since there are 10% recombinant; then

AZ = 5%

az = 5%

Therefore the probability of az gamete from the father =

= .05

each of the 46 original chromosomes splits into two daughter chromosomes, so there are two sets of 46 daughter chromosomes that end up in each cell. human cells have 46 chromosomes. each chromosome consists of a pair of identical chromatids attached together by a structure called a centromere.

answer; the above answer to the above statement is (true)