Individuals III-3 and III-4 are expecting their first child when they become aware that they both have a family history of this recessive condition. As their genetic counselor, you can calculate the probability that they are carriers and that their child will be affected with the condition.

1.) The probability that III- 3 is a carrier (Rr) =

2.) The probability that III - 4 is a carrier (Rr) =

3.) The probability that IV - 1 will be affected (rr) =

Options are 1/4, 1/2, 1/16, 1/3, 3/4, 2/3, 1/12, 1/6

The genealogy tree which is missing from the question is in the attachment.

1) P1 = ; 2) P2 = ; 3)P3 =

Explanation: 1) According to the genealogy tree, the individual III-3 has a P1 = 1/2, because each of the parents are heterozygous for the condition, since one of the ofspring is affected.

2) For individual III-4, one of the parents is heterozygous for the condition, so the probability of being a carrier is P2 = 1/2.

3) Now, for individual IV-1 be affected, the parents has to be carrier. So, this probability, depends on the probability of each parent being heterozygous and that the individual will be carrying the condition, which means:

P3 = 1/2 · 1/2 · 1/4 = 1/16.

The probability of having the condition is 1/16 or 6.25%.

succession returns a disturbed

ecosystem to a more stable state. this is also classified into two (2) types:

primary succession and secondary succession. the primary succession arises when

a new land is transformed and a bare rock has been exposed providing an environment

that can be occupied for the first time. while, secondary succession occurs

when a previously occupied environment was disturbed that kills much of all its

community

explanation: