One member of the serine protease family is trypsin. Trypsin cleaves the polypeptide chain by breaking the peptide bond after a lysine (lys) or arginine (arg) amino acid. What would be the product(s) if each of the following peptide molecules were treated with trypsin?
a. leu-thr-phe-ala-ser
b. trp-tyr-lys+ala-phe
c. 2lys+2-arg-va

The protease Trypsin would cleave the peptide molecules in the following ways below.

Explanation:

Each member of the serine protease family cleaves/cuts the bond after a specific amino acid of the substrate due to that specific amino  acid being recognized by a binding structure of the enzyme that is specifically created to bind that  specific amino acid. Therefore the protease would cleave the following peptide molecules in the following ways:

hey, i believe your answer would be d. sugar ribose and the base uracil. i believe this is the answer, because rna consists of sugar ribose, adenine, guanine, cytosine, and uracil.

your first option is incorrect, because that's dna. where it consists of sugar deoxyribose, adenine, guanine, cytosine and thymine.

your second option is also incorrect, this is because sugar deoxyribose is in dna, and uracil is in rna. these two do not make sense together.

your third option being incorrect, because sugar ribose is in rna, but not the base of thymine. rna consists of uracil, not thymine.

lastly your fourth option being correct! this answer is correct, because both sugar ribose, and the base uracil are in rna! ~

answer is d. sugar ribose and the base uracil.