In ducks, the trait for normal feathers is dominant to the trait for silky feathers. If
the male is hybrid for the trait of normal feathers and the female is homozygous for the
trait of silky feathers, then what would be the genotype and phenotype ratios of this
cross?

The genotype ratio is 2Ff : 2ff

The phenotype ratio is two normal feathered birds to two silky feathered birds.

Explanation: Let F represent the gene for normal feather and f represent the gene for silky feather. F is dominant while f is recessive, therefore a male that is hybrid for trait of normal feather is heterozygous and will have a genotype of Ff, a female that is homozygous for silky feather will have a genotype of ff.

A cross between Ff and ff will yield 2Ff birds and 2ff birds. Since F is dominant, a bird having genotype of Ff will manifest outwardly as blue feathered birds while ff will manifest outwardly as silky feathered birds because f is recessive and must occur in a homozygous condition in order to manifest phenotypically. Therefore, the genotype ratio is 2Ff: 2ff.

See the punnett square attached for more information

answer; i believe the correct answer is (sporophyte);

it creates acid rain