In a certain population of rabbits, the allele for brown fur is dominant over the
allele for white fur. if 10 out of 100 rabbits have white fur, what is the allele
frequency for the dominant allele?
the hardy-weinberg equation is:
[homozygous dominant]2 + 2[heterozygous] + [homozygous recessive]2 = 1
o a. 0.95
o b. 0.90
o c. 0.68
o d. 0.10

The allele  frequency for the dominant allele is 0.68.

C. 0.68

Explanation:

Let,

The Brown dominant allele be BB

The white recessive allele be bb

Frequency of white fur rabbit (bb) = 10/100 = 0.1

Therefore, q2 = 0.1

Frequency of recessive allele, q= √0.1

                                                  q = 0.316

Using Hardy Weinberg equation:

p+q = 1

p = 1-q

p = 1-0.316

p = 0.684

Thus, frequency of dominant allele, p = 0.684

vodka and hennesy

explanation: