Aslice of pizza has 500 kcal. if we could burn the pizza anduse all the heat to warm a 50-l container of cold water, what wouldbe the approximate increase in the temperature of the water? (note: a liter of cold water weighs about 1 kg.)
a. 50°c
b. 5°c
c. 10°c
d. 100°c
e. 1°c

c. 10°C

Explanation:

Given that: A slice of pizza has 500 kcal.

That is to say Q = 500kcal

If the pizza was burned and all the heat were used to warm a 50-L container of cold water,

what  would be the approximate increase in the temperature of the water?

We were also being told to note that; A liter of cold water weighs about 1 kg.

i.e 50-L container weighs about 50kg (mass)

∴ Since;

Q= 500kcal,

m = 50kg; &

the specific heact (c) = 1

we can find the approximate increase in the temperature of the water by using the formula:

Q = mcΔT

ΔT =

ΔT =

ΔT = 10°C

meteorologists would compare a new weather map with one 24 h old to see how fast a front is moving.