If flower position (axial or terminal) is inherited as it is in pease what will be the ratios of genotypes and phenotypes in the f1 generation resulting from the following cross axial red x terminal white?

Genotype ratio: 100% AaRr

Phenotype ratio: 100% axial and pink flowers

Explanation:

This is the complete question:  In some plants, a true-breeding, red-flowered strain gives all pink flowers when crossed with a white-flowered strain: RR (red) x rr (white) —> Rr (pink). If flower position (axial or terminal) is inherited as it is in pease what will be the ratios of genotypes and phenotypes in the F1 generation resulting from the following cross axial red x terminal white?

Let flower position allele be A.

Genotype of a true breeding axial red = AARR

Genotype of a true breeding terminal white = aarr

Crossing    AARR  x  aarr

All the progeny will have genotype AaRr

Since the flower position gene segregates according to Mendelian law (as seen in peas), A is dominant over a. However R exhibits incomplete dominance over r to give a pink colour.

Hence, the phenotype of the progeny will be axial flower position and pink flower color.

true, i don't really know what you're asking but from the info you provided im guessing the answer is true.

enzyme active site and substrate specificity

enzymes bind with chemical reactants called substrates. there may be one or more substrates for each type of enzyme, depending on the particular chemical reaction. in some reactions, a single-reactant substrate is broken down into multiple products