The incidence of cystic fibrosis, a recessive genetic disorder in the caucasian population of united states, is
in every 2,500 individuals. find the number of heterozygous carriers. (p + q = 1, p2 + 2pq + q2 = 1) a. 0.0392 b. 0.0254 c. 0.045

Cystic fibrosis occurs 1 in every 2,500 individuals.
Using Hardy Weinberg principle,
freq. of recessive allele/ q2 = 1/2500 = 0.0004
Take the square root,
q = 0.02
freq. of dominant allele/ p = q - 1
p = 0.98
freq. of heterozygous individuals = 2pq = 0.04

Therefore, the answer is 0.04, which is C.

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