If a restriction enzyme has as its recognition sequence "atccta," how many restriction sites would appear in the lambda genome, which is approximately 54,000 bp?

The number of restriction sites that would appear in lambda genome which is of  54,000 bp is 13.

Explanation:

The number of times a restriction enzyme can cut in a DNA sequence is one time for every 4ⁿ, where n is the total number of bases in that particular recognition sequence of the restriction enzyme. In this case the recognition sequence is ATCCTA which contains 6 bases.

So 4×4×4×4×4×4= 4056

Size of the genome= 54,000 bp

Number of restriction site= 54000÷4056 = 13.1 or 13

the correct answer is c   with the systems

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