You have a garden in which you would like to have only pea plants that have green seeds. (green seed color is recessive to yellow). you only have available yellow f1 seeds that were obtained by crossing green and yellow varieties. if you allow plants that arise from these seeds to self-pollinate, what proportion of the offspring could be used to initiate your pure-breeding pea garden?

% of the offspring could be used to initiate your pure-breeding pea garden

Explanation:

Given green color is recessive to yellow color.

In order to have only green color pea pods the Gardner must choose parents that have homozygous green genotype.

Let the allele for yellow color seeds be "Y" and green color seeds be "y"

Now if yellow seed after F1 cross is selected then its genotype would be Yy as it has been obtained after crossing true breeding yellow(YY) and green seeds(yy).

Now self pollination occurs between offspring of F1 generation i.e between Yy and Yy

So the offspring produced in second generation would be

Yy * Yy

YY, Yy, Yy, yy

Thus, out of four only one offspring  with genotype yy can be selected for producing pure breeding green seed pea plants

Thus, its probability is

%

mammal

explanation:

since there are no options posted i'll give you a few examples.

a dolphin's flipper, bird's wing, cat's leg.