The genetic frequencies of two separate populations are: aa aa aa population 1 .36 .48 .16 population 2 .55 .10 .35 a) what are the genotypic frequencies of the two populations? b) what are the allele frequencies? c) are the populations in hardy-weinberg equilibrium?

Explanation:

first solve for genetic frequency

Population 1

genetic frequency AA = 36/100 = 0.36

                               Aa = 48/100 = 0.48

                               aa = 16/100 = 0.16

Allele frequency

                            A = 0.36 + (0.5 x 0.48) = 0.60

                            a = 0.16 + (0.5 x 0.48) = 0.40

Population 2

genetic frequency AA = 55/100 = 0.55

                               Aa = 10/100 = 0.10

                               aa = 35/100 = 0.35

allele frequency

                            A = 0.55 + (0.5 x 0.10) = 0.60

                            a = 0.35 + (0.5 x 0.10) = 0.40

Weinberg equilibrium states that the allele frequency of a population will remain the same from generation to generation or else there is a catastrophic activity.

from the calculations above, assuming population 1 and 2 are two different generations, it is perfectly in Weinberg equilibrium because the allele frequency is the same.

an active site is a region that is present on an enzyme where the reactants or the substrate molecules we can say bind and experience a chemical reaction. the substrate is basically a reactant whose concentration is changing and that is converting into a product after binding at the active site of an enzyme