Part 2: crossing beak color and feather color cross beak color and feather color. cross one parent that is heterozygous for both beak color and feather color with a parent that is homozygous for both recessive traits. what are the genotypes of the parents? (hint: recall that the p generation includes a heterozygous parent with dominant traits and a homozygous parent with recessive traits.)

The genotype of the heterozygous parent= BbFf

The genotype of the homozygous recessive parent= bbff

Explanation:

Let's assume that the allele "B" gives the dominant beak color while the allele "b" gives the recessive beak color. Likewise, the allele "F" imparts the dominant color to the feathers while the allele "f" gives the recessive color to the feathers. A parent heterozygous for beak color and feather color would have one copy of each dominant and recessive alleles for both the genes. On the other hand, the homozygous recessive parent would have two copies of the recessive alleles for the mentioned genes.  

According to the given information, the one parent is heterozygous for both beak color and feather color and the other parent is homozygous for both recessive traits.

The genotype of the parent that is heterozygous for both beak color and feather color= BbFf

The genotype of the parent that is homozygous for both recessive traits= bbff

sand 60

clay 10

silt 30

sandy loam should be dominated by the sand. as the amount of sand increased, the amount of slit needed to anchor the plants' roots to the sand will also be increased. even though the amount is very little, 10% part of clay is still necessary for proper oxidation.

-hails tea

explanation:

-t poses