Consider the following double-stranded dna sequence that codes for a short polypeptide. 5'-a-t-g-t-g-g-c-c-a-c-t-a-t-a-a-t- c-a-3' 3'-t-a-c-a-c-c-g-g-t-g-a-t-a-t-t-a- c-t-5' which strand is the coding strand, and where is the n-terminal end of the resulting peptide located? consider the following double-stranded dna sequence that codes for a short polypeptide. 5'-a-t-g-t-g-g-c-c-a-c-t-a-t-a-a-t- c-a-3' 3'-t-a-c-a-c-c-g-g-t-g-a-t-a-t-t-a- c-t-5' which strand is the coding strand, and where is the n-terminal end of the resulting peptide located? the bottom strand is the coding strand, and the n-terminus is on the right. the bottom strand is the coding strand, and the n-terminus is on the left. the top strand is the coding strand, and the n-terminus is on the left. the top strand is the coding strand, and the n-terminus is on the right. not enough information is given to answer the question.

Not enough information is given to answer the question.

Explanation:

The top strand has the inititation codon, ATG, so by logic this should be the coding strang. However, considering that is a complete sequence for a short peptide, it fails to have a termination codon, since in this case the last codon is TCA, which codes for the aminoacid Serine. The termination codons for DNA are TAATermination (ochre), TAGTermination (amber) or TGATermination (opal or umber). So, the top strand has the iniciaiton codon, but lacks the termination, so this is incomplete to make the statement of this strand being coding the short peptide.

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explanation:

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