A5.0-g egg falls from a 90-cm-high counter onto the floor and breaks. what impulse is exerted by the floor on the egg?

0.021 kgm/s

Explanation:

using energy

change potential energy of the egg = change in kinetic energy of the egg

mgh = 1/2 mv² m in kg, h in meters

5.0g = 5.0/1000 kg= 0.005 kg

90 cm = 90 / 100 = 0.9 m

cancel m on both side

gh = 1/2 v²

make v subject of the formula

v = √2gh = √2×9.81×0.9 = √17.658 = 4.2 m/s that is the velocity of the egg on impact with floor and the initial velocity of the egg is zero.

impulse = m × Δv = 0.005 × 4.2 = 0.021 kgm/s

i believe you meant to say air rather than hair so the answer is below ")

the dead sea, the lowest place on earth at 430 metres (1,410 ft) below sea level, has a correspondingly high typical atmospheric pressure of 1065 hpa.

yes? sounds right, but you didn’t ask a question.