In jabberwocks, flame eyes (f) are dominant to blue eyes (f) and burbling (b) is dominant to whistling (b). jabberwock geneticists suspect that the two genes are linked in one of the autosomes. they mate a true-breeding, flame-eyed, burbling female with a true-breeding, blue-eyed whistling male. they then mate a pair of offspring. what ratio of genotypes would you expect if the genes were not linked? (remember you are crossing ffbb x ffbb)

FFBB      1/16

FFBb      1/8

FfBB       1/8

FfBb       1/4

FFbb       1/16

Ffbb       1/8

ffBB        1/16

ffBb        1/8

ffbb        1/16

Explanation:

True breeding flame-eyed, burbling female = FFBB

True breeding blue-eyed, whistling male = ffbb

Mating FFBB with ffbb, resulting offspring will be FfBb

Crossing FfBb with another FfBb and assuming the genes are not linked, resulting offspring genotypic ratios will be:

FFBB      1/16

FFBb      1/8

FfBB       1/8

FfBb       1/4

FFbb       1/16

Ffbb       1/8

ffBB        1/16

ffBb        1/8

ffbb        1/16

The phenotypic ratios will be:

F_B_    9/16  (flame-eyed, burbling)

F_bb     3/16 (flame-eyed, whistling)

ffB_       3/16 (blue-eyed, burbling)

ffbb        1/16 (blue-eyed whistling)

answer: c

explanation:

both male and female gametes are produced by meiosis of the germ cells. therefore, both male and female gametes are haploid. one male and one female gamete unite during the fertilization to form the diploid zygote. in seed bearing plants, pollen grain is the male gametophyte, which produces sperm cells.