Aresearcher planted 160 seeds from an f2 cross of two hybrid purple flowered plants and got 123 purple flowered progeny and 37 white flowered progeny. what was the chi- square value for this result?
how do we find the expected value for this problem if we are given the observe value?

Chi square value = 0.3

In order to find the expected value, an assumption of purple flower colour dominance over white flower colour has to be made.

Explanation:

First, we will assume that the purple flower trait is dominant over white flower trait, and that the alleles segregate according to Mendelian standard. Hence, the expected F2 phenotypic ratio will be 3:1.

In order to get the Chi square, the expected phenotype frequency will be calculated thus;

Expected frequency (E) for purple flowered plants = 3/4 x 160 = 120

Expected frequency (E) for white flowered plants = 1/4 x 160 = 40

Observed frequency (O) for purple flowered plants = 123

Observed frequency (O) for white flowered plants = 37

Chi square =

For the purple colour flower

, which gives 0.075

For the white colour flower

, which gives 0.225

Total = 0.075 + 0.225, which gives 0.3

not only is it colder, it also becomes darker, less salty, and more dense.