In humans, rh-positive individuals have the rh antigen on their red blood cells, while rh-negative individuals do not. if the rh-positive phenotype is produced by a dominant gene (a), and the rh-negative phenotype is due to its recessive allele (a), what is the frequency of the rh-positive allele if 84% of a population is rh-positive? a. 0.04.b. 0.16.c. 0.48.d. 0.60.e. 0.84.

D. 0.60

Explanation:

If the population is in Hardy-Weinberg equilibrium, the genotypic frequencies are:

p is the frequency of the Rh positive allele (A) and q is the frequency of the Rh-negative allele (a).

If 84% of the population is Rh-positive, then 16% is Rh-negative and has the genotype aa. Therefore:

q² = 0.16

q = √0.16

q=0.4

And because p+q=1,

p = 1 - 0.4

p = 0.6

The frequency of the Rh-positive allele is 0.6

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