(mendelian genetics) consider three gene pairs aa, bb, and cc. the uppercase letter is the dominant allele and each gene pair assorts independently of each other. what is the probability of obtaining an offspring displaying the a b c phenotype (that is having the dominant phenotypes for each of the three genes) from a cross of aa bb cc x aa bb cc parents?

9/16

Explanation:

The cross was Aa Bb CC X Aa Bb cc

Because genes assort independently, we can analyze each of them separately in the cross, calculate the probability of getting offpsring with a dominant allele, and then multiply each of those probabilities to obtain the overall probability of having A_B_C_ progeny.

A/a

Aa x Aa ---> 3/4 A_, 1/4 aa

B/b

Bb x Bb ---> 3/4 B_, 1/4 bb

C/c

CC x cc ---> 1 C_

3/4 × 3/4 × 1 = 9/16 A_B_C_ offspring.

all matter is made up of atoms

in any element all atoms are the same

elements in a compound are always in a constant ratio: apex

weathering - colorado river carves land in arizona to form the grand canyon. cracks form in a sandstone wall surrounding a house. a marble statue near the science museum is changing color due to rainfall

erosion - after a rainstorm, soil and rock piees litter the roadways. the sand dunes in the sahara desert are changing shape.

here's your answer.