12 analyze what mass of radioactive isotope
will be left after three half-lives?

1/8 of original sample.

Explanation:

Consider your final amount is 100 g.

After three half lives:

at 0 = 100 g

1 half life = 100/2  = 50 g

2 half life = 50/2 = 25 g

3 half life = 25/2 = 12.5 g

Know multiply the amount after three half lives with 8.

12.5 g × 8 = 100 g

So, after three half lives 1/8 of original sample is present.

1. (1.2kw)x(15/60hours) = .3kwh --> a

2. (5kw)x(90/60hours)x(8cents/kwh) = $0.60 --> d

3. microwave --> 1200 watts = (1.2kw)x(6/60hours) = .12kwh

coffee-maker --> 900 watts = (.9kw)x(10/60hours) = .15kwh

therefore, it requires more energy for the coffee-maker to do the same amount of work.

so the answer is a.

hey bro i looked it up on google the structure of the eye-spot in euglena viridie, e. ehrenbergii, and phacus pyriyorme is not as franzé haa described it. the so-called “crystal body” and “lens bodies” were not found in any of the individuals of the species examined by me. as earlier observers have stated, the eye-spot consists simply of a mass of pigment granules arranged in a single layer, and probably embedded in a protoplasmic framework, but the latter could not be seen, and its presence was only inferred from the fact that the pigment granules must be held together in some way, thd the eye-spot as a whole is capable of expansion, and that the pigment granules can be separated from each other.

hope this   and an i get brainlsiest