In fenzars, the genes for twisted horns (t) and purple lips (p) are 12 map units apart. phenotypically wild-type females (t+p / tp+) were mated to twisted-horned males with purple lips. what percent of offspring would you expect to have twisted horns and wild type lips? group of answer choices

44%

Explanation:

Parent 1 : wild type = t+p/tp+

Parent 2: recessive type = tp/tp

If t and p genes are 12 map units apart that means that they are linked genes and can have 12% recombinants. Parental type offspring would be 88%. Here parental gametes from parent 1 are t+p and tp+.

When tp+ gametes combine with tp gametes from parent 2 we will get the genotype tp+/tp which will result in twisted horns and wild type lips. Out of the total 88% parental type offspring, this genotype would be 44% since t+p/tp will make rest 44% offspring genotype.

Hence, 44% offspring would have twisted horns and wild type lips.

d. in sexual reproduction, offspring have more chromosomes than

either parent.

asexual reproduction results in offspring which are genetically the same as the parent organism (not counting a rare mutation). sexual reproduction produces a random mixture of the genetics derived from both parents

explanation:

some of your causes might be acidic rain or natural wildfires that cause the parks to be degraded

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