Biology

Biology, 25.10.2019 02:43, cravingnafi202

Assume that the genes for tan body and bare wings are 15 map units apart on chromosome ii in drosophila. assume also that a tan-bodied, bare-winged female was mated to a wild-type male and that the resulting f1 phenotypically wild-type females were mated to tan-bodied, bare-winged males. of 1000 offspring, what would be the expected of wild-type offspring, and in what numbers would they be expected

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Biology, 28.06.2019 05:00, chloesmolinski0909

The genes for mahogany eyes and ebony body are approximately 25 map units apart on chromosome 3 in drosophila. assume that a mahogany-eyed female was mated to an ebony-bodied male and that the resulting f1 phenotypically wild-type females were mated to mahogany, ebony males to obtain an f2 generation. part a which of the following phenotypes would be expected in the f2 offspring? select all that apply. wild type mahogeny-eyed ebony-bodied mahogeny-eyed, ebony-bodied submitmy answersgive up correctpart b if 1000 f2 offspring are obtained, how many flies of each phenotype are expected? __wild type : __ mahogeny : __ ebony : __ mahogeny, ebony (remember the two genes are 25 mu apart on the same chromosome. in order to determine how many offspring of each type are produced, you must determine if the f1 females carries both mutations on one chromosome, and wildtype alleles on the other or if she carries one mutation and one wildtype allele on each chromosome.) enter your answer as the number of flies of each phenotype separated by a colon.

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Biology, 28.06.2019 06:50, alwaysneedhelp84

The genes for mahogany eyes and ebony body are approximately 25 map units apart on chromosome 3 in drosophila. assume that a mahogany-eyed gray bodied female was mated to an red eyed ebony-bodied male and that the resulting f 1 phenotypically wild-type (red eyed, gray bodied) females were mated to mahogany, ebony males to obtain an f 2 generation. which of the following phenotypes would be expected in the f 2 offspring? hint: really pay attention to what the question is asking you to cross - approach this in a step-wise fashion and you should be

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Biology, 12.09.2019 20:30, juliannabartra

In drosophila, a cross was made between a yellow- bodied male with vestigial (not fully developed) wings and a wild-type female (brown body). the f1 generation consisted of wild-type males and wild-type females. f1 males and females were crossed, and the f2 progeny consisted of 16 yellow-bodied males with vestigial wings, 48 yellow-bodied males with normal wings, 15 males with brown bodies and vestigial wings, 49 wild-type males, 31 brown-bodied females with vestigial wings, and 97 wild-type females. explain the inheritance of the two genes in question based on these results.

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Biology, 12.09.2019 21:20, bluepanda21

The recessive alleles for yellow body (yb) and cut wings (cw) identify two autosomal genes on the second chromosome of drosophila melanogaster. when females, heterozygous at these two genes (yb+yb cw+cw), were crossed with yellow-bodied, cut-winged males, the following classes and numbers of progeny (out of 1000) were obtained: a. wild type body color, wild type wings 120 b. wild type body color, cut wings 360 c. yellow body color, cut wings 140 d. yellow body color, wild type wings 380

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