In a population of 100 individuals, 50 are genotype mm, 40 are mn, and 10 are nn. what are the frequencies of the m and n alleles in this population? in a population of 100 individuals, 50 are genotype mm, 40 are mn, and 10 are nn. what are the frequencies of the m and n alleles in this population? f(m) = 0.5, f(n) = 0.5 f(m) = 0.1, f(n) = 0.9 f(m) = 0.9, f(n) = 0.1 f(m) = 0.3, f(n) = 0.7 f(m) = 0.7, f(n) = 0.3

F(M) = 0.7 F(N)=0.3

Explanation:

We need to take into account that individuals NN and MM only N or M aleles respectively while MN gives just half of the allelic contribution for each. With this in mind we have the following probabilities for getting each of the alleles: MM => p(M) = 1.0 and p(N)=0.0

MN => p(M ) = 0.5 and p(N) = 0.5

NN => P(M) = 0.0 and p(N) = 1.0

With this we can calculate the frequencies of the M and N alleles in the population with 100 individuals using the following formulas

For f(M):

The frequency of the M allele is 0.7

For f(N):

The frequency of the N allele is 0.3

the answer would be 2, if crossing over doesn’t occur 2 out of 4 of the daughter cells will have that allele.

hope this : )

b ti isnfornopgnoernfrof