Freckles are dominant over no freckles. stacey is hybrid for freckles. her husband, charlie, does not have any. if they have four children, how many will have freckles?

2 children will have freckles

Explanation:

This question is just a play on words for the punnet square. You have a dominate trait , freckles, and a recessive trait, no freckles. Charlie has no genes for freckles, so he will be represented as 2 lower case letters. Stacey has both types of genes for freckles and no freckles, so she will be represented as 1 capital letter and 1 lowercase letter. I'll try to make a punnet square down below. Capital A represents the dominate trait and lowercase a represents the recessive trait.

         A            a

a       Aa          aa

a       Aa          aa

As you can see, 2 of her children have the dominate trait for freckles, and two of her children only have recessive traits, which means no freckles:)

the offspring would all be white. if the parents are both white flowers then they have the genotype rr, which when crossed results in an all white punnet square.