Phenylketonuria (pku) is a disease caused by a recessive mutation. pku is extremely common in ireland, affecting approximately 1 in 4500 live births. assuming that the population is in hardy-weinberg equilibrium, what is the frequency of homozygous wild-type individuals (i. e., people without the recessive mutation)? phenylketonuria (pku) is a disease caused by a recessive mutation. pku is extremely common in ireland, affecting approximately 1 in 4500 live births. assuming that the population is in hardy-weinberg equilibrium, what is the frequency of homozygous wild-type individuals (i. e., people without the recessive mutation)? 98.5% 2.96% 97% 1.5% 0.022%

97%

Explanation:

PKU is caused by a recessive mutation, which means that affected individuals are homozygous and recessive (tt).

The frequency of genotypes according to Hardy-Weinberg equilibrium is:

where p is the frequency of the T allele and q is the frequency of the t allele.

Affected individuals are 1 in 4500, which means the frequency of tt genotype is 1/4500.

If the population is in Hardy-Weinberg equilibrium,

The sum of the allele frequencies adds up to 1, therefore:

p + q = 1

p= 1 - q

p= 1 - 0.015

p= 0.985

The frequency of the TT genotype (homozygous wild-type individuals) will be:

97% of the population will have the homozygous wild-type TT genotype.

the answer is "a.) well–developed vascular system."

explanation:

the answers are as following:

1. c. double helix, nucleosome, coil, supercoil, chromosome

2. b. g2 phase, preparation for mitosis

3. d. interphase consists of the g1, s, and g2 phases

4. c. metaphase

5. a. chromosomes are duplicated before cell division so that each new daughter cell has a complete set