Biology

Biology, 11.10.2019 05:10, Powerhickory1313

(1) what staggering achievement in "precision cosmology” has recently been determined?

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Engineering, 31.10.2019 00:31, cassidy100117

Given the expression, viz (-1/3) (2n + 1) a. write a matlab program in a script file hw6p3a.m that does the following: 1. (4 pts) determines the value of the expression above for a given m, entered by the user. use a for loop to determine the value of the expression by adding terms to the sum. ii. (2 pts you should notice that the value of the expression determined by your program approaches the value of pi in matlab as the number of terms increases. create a variable called prec (refers to precision), which refers to the absolute difference between the value of the expression and the value of pi in matlab. iii. (2 pts) use fprintf before the end of the loop to display the results as: for n = 1, value = x. to a precision of x. for n = 2, value = x. to a precision of x. use format i %.15f, $.10e for n, the value of expression, and the precision respectively. iv. (2 pts) use your program with m = 5 and 15. b. (4 pts) modify your program and save it to a new script file hw6p3b.m to terminate the loop once the precision reached a tolerance of 10–5. this can be done using a break statement. deactivate the printing inside the loop, instead, once the loop is terminated, the program must display the last value of the expression and how many passes the program takes to reach this value as a value of x. in xx passes with a precision of x. use format 8.15, %2i, 4.6e for the value of expression, n, and the precision, respectively. (1 pt) run this case with m = 100.

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