Ebony body, held-out wings and sepia eyes are all recessive and all on chromosome 3. the coefficient of coincidence for chromosome 3 is 0.5. a homozygous ebony male is mated to a homozygous held out wing and sepia eyed female. the f1 are wild-type. an f1 female is test crossed to a fly that is homozygous for all three recessive alleles and they produce 1000 progeny. if ebony and held-out are separated by 12 map units, and held-out and sepia are 14 map units apart, and if the order of these loci is ebony, held-out, and sepia: how many ebony, sepia (but not held-out) progeny are expected from this test cross?

what have scientists found to be the most efficient and effective way to insert new sequences into an individual? a-scientists have created genetically altered foods that release dna during digestion. b-scientists use viruses to insert specific gene sequences. c-scientists irradiate genes so that they can be absorbed through the skin.

the denominator has a very specific role.

answer: 45

explanationyou have to add as well to be it could be

regents of the university of california v. bakke, 438 u.s. 265 (1978), was a landmark decision by the supreme court of the united states. it upheld affirmative action, allowing race to be one of several factors in college admission policy.