You set up the following cross: aa: bb: cc: dd x aa: bb: cc: dd what proportion of the offspring should have the genotype aa: bb: cc: dd? assume all alleles represented by capital letters are dominant and all genes are independently assorting.

The correct answer is 1/64

Explanation:

Given cross is AaBbCcDd x aaBbCcdd

Now, if we consider the cross Aa x aa, the probability of having Aa is 2/4

Similarly, for Bb x Bb, the probability of having bb is 1/4

Cc x Cc, probability of having CC is 1/4

Dd x dd, probability of having dd is 2/4

Thus, the probability or proportion of the offspring to have genotype AabbCCdd = 2/4 x 1/4 x 1/4 x 2/4 = 4/256 = 1/64

Thus, only one out of 64 offspring is expected to have this genotype.

Alternatively, one can draw the Punnett square of AaBbCcDd x aaBbCcdd

Total number of possible genotype combination which can be formed from above cross can be found using the formula 2ⁿ where n is the number of heterozygous pairs.

In AaBbCcDd, there are 4 heterzygous pair and in aaBbCcdd, there are 2 heterozygous pairs.

Thus, n =6

2⁶ = 64

16 type of gametes will be formed by AaBbCcDd and 4 types of gametes will be formed by aaBbCcdd.

videntify the dna change shown in the diagram and explain how that change can result in the increased genetic diversity often seen among siblings.identify the dna change shown in the diagram and explain how that change can result in the increased genetic diversity often seen among siblings.