In europe, approximately 4% of people are red-haired, mostly due to a recessive mutation in the melanocortin 1 receptor (mc1r). if the population is in hardy-weinberg equilibrium, what is the likelihood that a non-redheaded european is a carrier for the mc1rr allele? (for the purpose of this problem, assume all redheads and carriers are mutant for the same mc1r allele).
a: 22%
b: 33%
c: 11%
d: 44%

33%.

Explanation:

The 4% population is red-hair due to the recessive mutation in melanocortin 1 receptor (MC1R).

Since, the population is in Hardy-Weinberg equillibrium- laet the frequency of recessive allele with red - hair is 'q' and the frequency of dominant allele in the population is 'p'.

q=0.2

According to hardy-weinberg equillibrium

(p+q)=1

p=1-q

p=1-0.2

p=0.8.

The total population with non red hair is calculated by

=

= 0.64 + 0.32

= 0.96

The percentage of the population with non red headed carrier for MC1Rr is calculated by:

=0.32/0.96*100

=33%

Thus, the correct answer is (B).

the answer is b)3/8x+1

population. population is the number of people or animals in a particular place. an example of population is over eight million people living in new york city.

here is your answer hope i .