In a population with two alleles, b and b, the allele frequency of b is 0.8. what would be the frequency of heterozygotes of the population is in hardy weinberg equilibrium?

explain everything and all of the math

0.32

Explanation:

We will use the following equations;

p + q = 1

p2 + 2pq + q2 = 1

Therefore;

If B = 0.8; then b = 1 – 0.8 = 0.2

Heterozygous population is represented by 2pq; 2 * 0.8 * 0.2 = 0.32

if the hares very faster than they are now, and thus the lynx's hunting success rate drops because it will be harder to catch them, the rate that will change will be the pray-rate. the pray-rate will change because more hares will be able to survive, thus more individuals for reproduction, so the end result will be increasing population of hares.

the predator-rate will remain pretty much the same because there will be more than enough pray, but the hunting success rate is stagnant.