If a pea plant that is herterozygous for rounds, yellow peas is crossed with a pea plant that is homozygous for round peas but heterozygous for yellow peas, how many different phenotypes are their offspring expected to show?

There re two different types of phenotypes in the offsprings that is Round yellow and Round green.

Explanation-

As per the Mendelian inheritance, Round shape and yellow color of pea are dominant over wrinkled shape and green color of pea.

According to the question, genotypes of parents are- RrYy ( heterzygous for round and yellow) and RRYy ( homozygous for round and heterozygous for yellow).

The first parent can produce four different gametes that is RY, Ry, rY, ry whereas the second parent will produce only two types of gametes that is RY and Ry.

When they are crossed, they will produce two different phenotypes in the offsprings.

Refer punnett square.

this is true, assuming that the allele is completely recessive and incomplete dominance is not a factor.

nucleic acid molecules are incredibly complex, containing the code that guarantees the four different nucleotide units comprise dna, the nucleic acid of interest to the genealogist. and one of four nitrogen-containing molecules called nucleotides