If a cubical cell with with 2 cm sides doubles the dimensions of its sides what change occurs to the ratio of its surface area to volume

The surface area of a cell is  6 × side² and volume of a cubical cell is side³.

Surface area of  cell having side 2 cm = 6 × 2 × 2 = 24 cm²

volume of the cell = 2 ×2 × 2 = 8 cm³

Therefore, surface area to volume ration is 24÷8 = 3 : 1

If the side of a cell is doubled,  then

Surface area of cell = 6 × 4 × 4 = 96 cm²

volume of the cell = 4 × 4 × 4 = 64 cm³

Therefore, surface area to volume ration is 96 ÷ 64 = 3 : 2  

Surface area to volume ratio decreases.

make   gliitsh plesea   !

after a the power stroke, adp is released, but the cross-bridge formed is still in place. atp then binds to myosin, moving the myosin to its high-energy state, releasing the myosin head from the actin active site.