In a certain population of rabbits, the allele for brown fur is dominant over the allele for white fur. if 10 out of 100 rabbits have white fur, what is the allele frequency for the recessive allele? the hardy-weinberg equation is: [homozygous dominant]2 + 2[heterozygous] + [homozygous recessive]2 = 1

The Hardy-Weinburg equation is p + q = 1, or p^2 + 2pq + q^2 = 1, where p is dominant and q is recessive. If 10 out of 100 rabbits have white fur, 10% of the rabbits have white fur. Therefore, 90% of the rabbits have brown fur, which can be substituted into the first equation to become 0.9 + 0.1 = 1. Now that we know what p and q equal, we can solve the rest of the equation.

0.9^2 = 0.81

0.9 * 0.1 * 2 = 0.18

0.1^2 = 0.01

Therefore, the allele frequency of the recessive allele is 0.1

yes? sounds right, but you didn’t ask a question.

hypoxemia refers to a below usual concentration of oxygen in the blood, mainly in the arteries. hypoxemia is an indication of an issue associated with circulation or breathing and may lead to various symptoms like shortness of breath.  

the condition is identified by determining the level of oxygen in the blood sample obtained from an artery. it can also be predicted by determining the oxygen saturation of the blood with the application of a pulse oximeter.  

the normal arterial oxygen is about 75 to 100 mm hg. the values underneath 60 mm hg is generally considered with the requirement for supplemental oxygen. the normal pulse oximeter readings generally range between 95 to 100 percent. the values under 90 percent are regarded as low.  

in the given case, the oxygen saturation is measured at 93 percent, hence, there is no need to administer oxygen, that is, one should withhold oxygen.