In a population at hardy-weinberg equilibrium with two alleles, a and a, 264 of the 1200 individuals display the recessive trait (aa). what is the estimated frequency of the a allele?

Assuming that this population is in Hardy-Weinberg equilibrium, the estimated frequency of the a allele is 0.47. And the estimated frequency of the A allele is 0.53.

The Hardy-Weinberg equilibrium theory states that the allelic frequencies in a locus are represented as p and q. Assuming a diallelic gene,

•p ⇒ frequency of the dominant allele,

•q ⇒ frequency of the recessive allele.

•p² (H0m0zyg0us dominant genotypic frequency),

•2pq (Heter0zyg0us genotypic frequency),

•q² (H0m0zyg0us recessive genotypic frequency).

If a population is in H-W equilibrium, it gets the same allelic and genotypic frequencies generation after generation.

The addition of the allelic frequencies equals 1

p + q = 1.

The sum of genotypic frequencies equals 1

p² + 2pq + q² = 1

According to this framework, to get the allelic frequency, first we should take the genotypic frequency of the recessive trait, F(aa).

F(aa) = q² = 264 / 1200 = 0.22

Now, we can get the allelic frequency f(a) = q

f(a) = q = √q² = √0.22 = 0.469 ≅ 0.47

Fynally, we can get f(A) = p by clearing the following equation,

p + q = 1

p = 1 - q

p = 1 - 0.47

p = 0.53

The estimated frequency of the a allele is 0.47.

The estimated frequency of the A allele is 0.53.

You can learn more about the Hardy-Weinberg equilibrium at

link

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1.agranulocytes

2.granulocytes

the monocytes or macrophages of agranulocytes , dendritic cells which are accessory leucocytes, and b cells which is one type of lymphocytes   identify the antigens present on the pathogen's surface. these three cells are called antigen presenting cells(apc) which are phagocytes and destroy the antigens by secreting antitoxins. besides this leukocyte is always plays vital role in the immunity of the body.

there is no stairs in bungalow

explanation:

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