Sheila weights 60 kg and is riding a bike her momentum on the bike is 340 kg m/s the bike hits a rock which stops it completely and throws sheila forward onto the pavement if there is no net force on the system what is sheila’s velocity immediately after she thrown from the bike.

This question is based on law of conservation of momentum, which says total total momentum of the system is equal to total momentum of the system after collision.

Before collision, = 340 kg m/s

After collision, = mass * velocity = 60 kg * v

Here, we need to find the velocity with which Sheila was thrown after the collision.

According to law of conservation of momentum,

=

340 = 60 * v

v = 340 / 60 = 5.667 m/s [approximately]

The speed with which Sheila was thrown from the bike is 5.667 m/s.

it has one origin of replication, but it proceeds in two directions - d)

this is a good question! i'll do some research and come back when i have the answer!