If a woman who is homozygous for almond shaped eyes (aa) marries a man who is heterozygous for almond shaped eyes (aa), what are the possible genotypes and phenotypes of their children

Genotypes 2 AA and 2 Aa

All offsprings' eye will be Phenotypically almond-shaped

Explanation:

This is a typical monohybrid cross involving a single gene coding for eye shape in humans.

From the information given in the question, a woman whose eye is phenotypically almond-shaped (AA) marries a man whose eye is also phenotypically almond-shaped (Aa).

The woman is homozygous i.e. same allele, for the trait while the man is heterozygous i.e. different alleles, for the trait.

In a cross between the two individuals, each allele gets separated into gametes according to Mendel's law of segregation. (See attached image).

According to the cross as depicted in the image, four possible offsprings will be produced in which all will be expected to have an almond-shaped eye.

2 of the offsprings genotype will be homozygous (AA) while the other 2 will be heterozygous (Aa).

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