Advanced Placement (AP), 17.04.2021 03:30, kingb59

The Case of Kline and Myers This a a 2 part assignment, part 1 is an optional assignment. Part 2 is an SBLA grade.
1. You may turn in a timeline and case notes that you used to develop a solution.
a. This is worth 30 points if completed (it will not harm your grade to not turn this in).
b. It is either 30 for having a timeline and notes, or 0 points for not.
Please attach this as a separate file to the assignment on Classroom.
2. SBLA-You are turning in a statement in which you decide on the guilt of one of the suspects.
You need to defend this claim with evidence and reasoning. It will be scored with the rubric
below.
C.

Answers: 1

Show answers

Answers

answered: Guest

Answer dot(3) is most used;

answered: Guest

Answer: the interval on which the curve is concave up is (-∞, -1/2)====== $\displaystyle y = \int_{0}^x \frac{1}{1 + t + t^2} \; dt$ we find the interval where this curve is concave up by finding the interval in which the 2nd derivative is positive.differentiate the curve equation with respect to x $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \end{aligned}$ let the function f denote be the anti-derivative of the inside expression, i.e. a function such that $(d/dx)f(x) = 1/(1 + t + t^2)$ .then use the fundamental theorem of calculus: $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \\& = \frac{d}{dx} \big[ f(x) - f(0) \big] & & \text{\footnotesize apply ftc} \\ & = \frac{d}{dx}f(x) - 0 \\ & = \frac{1}{x + x + x^2} & & \text{\footnotesize since $\frac{d}{dx}f(x) = \frac{1}{1 + x + x^2}$ } \end{aligned}$ differentiate again to get second derivative. we can use chain rule with 1/x as the outside function and 1 + x + x² as the inside function $\begin{aligned} \frac{d}{dx} \left( \frac{dy}{dx} \right) & = \frac{d}{dx}\left(\frac{1}{1 + x + x^2} \right) \\ \frac{d^2y}{dx^2} & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot \tfrac{d}{dx}(1 + x + x^2) \\ & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot (1 + 2x) \\ & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \end{aligned}$ find critical numbers of the second derivative. these numbers are where the 2nd deriv. is undefined or zero.where the 2nd derivative is zero: set (d²y/dx²) to equal 0 and solve for x $\begin{aligned} 0 & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \\ 0 & = -(1+2x) \\ -1 & = 2x \\ x & = -1/2 \end{aligned}$ where the 2nd derivative is undefined: if the denominator is equal to zero, the derivative will be undefeined. attempting to solve the equation 1 + x + x² = 0results in a discriminant of $b^2 - 4ac = 1^2 - 4(1)(1) = -3$ meaning that the equal 1 + x + x² = 0 has no real solutions and therefore will never equal zero.======our only critical number is x = -1/2.this forms two intervals to test the sign for: (-∞, -1/2) and (-1/2, ∞)test values into the 2nd derivative for (-∞, -1/2)if we try x = -1, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = -1} & = \frac{-(1+2(-1))}{\left(1+(-1)+(-1)^2\right)^2} \\ & = \frac{-(1-2)}{1} \\ & = 1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave up on (-∞, -1/2)test values into the 2nd derivative for (-1/2, ∞)if we try x = 0, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = 0} & = \frac{-(1+2(0))}{\left(1+(0)+(0)^2\right)^2} \\ & = \frac{-(1)}{1} \\ & = -1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave down on (-∞, -1/2).the interval on which the curve is concave up is (-∞, -1/2)

answered: Guest

Ithink the answer is d

answered: Guest

This is called visual imagery. it is a memorization technique wherein an idea or a term is associated with an image, this in remembering ideas, especially as humans are very visual learners. this is also why visual aids a lot for memory retention.

Other questions on the subject: Advanced Placement (AP)

Advanced Placement (AP), 24.06.2019 09:00, albattatasraap5wymy

Based on what you've learned about the professions, which ones appeal to you as a potential career and why? if none interest you as a future career, indicate another career you're interested in and explain why that career interests you.

Answers: 1

continue

Advanced Placement (AP), 26.06.2019 03:30, n987

Question 12 which was not a reason the industrial revolution began in england? a) leading world exporter b) favorable finance institutions c) independent local governments d) large labor force question 14 who did not lead the fight to end slavery? a) william wilberforce b) toussaint l’ouverture c) simón bolívar d) olympe de gouges question 15 which was not an underlying cause of the revolutions of 1830 and 1848 in europe? a) increasing aristocratic discontent b) budding romantic movement c) rising tide of nationalism d) growing liberal spirit

Answers: 2

continue

Advanced Placement (AP), 26.06.2019 08:00, babyduck0664

Type the correct answer in the box. spell all words correctly. what regulations are provided to ensure that the physical location of a childcare center conforms to required regulations set by the respective governing body of that area? are provided to ensure that the physical location of a childcare center conforms to required regulations set by the respective governing body of that area.

Answers: 3

continue

Advanced Placement (AP), 26.06.2019 22:30, BreadOfTheBear

Aperiodontist mainly treats patients with

Answers: 2

continue

Do you know the correct answer?

The Case of Kline and Myers This a a 2 part assignment, part 1 is an optional assignment. Part 2 is...