When 3000 g of water is cooled from 80.0C to 10.0C, how much heat energy is lost?

The quantity of heat lost is equal to 877,800 Joules or 8778 Kilojoules.

Given the following data:

Mass of water = 3000 grams.Initial temperature = 10.0°C.Final temperature = 80.0°C.

Scientific data:

Specific heat capacity = 4.18 J/g °C.How to calculate the quantity of heat lost.

Mathematically, the quantity of heat lost is given by this formula:

Where:

m is the mass.c is the specific heat capacity. is the change in temperature.

Substituting the given parameters into the formula, we have:

Q = 877,800 Joules or 8778 Kilojoules.

Read more on heat capacity here: link

Extrusive;

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