What quality does the CBO have that Congressional committees lack?
How does the government use monetary policy to try to steer the economy?
Why does the growth of entitlement spending pose a challenge for the government?
What were the two specific parts of the Supreme Court’s decision in the Bakke case (1978)?
How is Brown v. Board of Education (1954) related to the Equal Protection Clause?
What are the various parts of the Civil Rights Act of 1964?
What power did Congress use to pass civil rights legislation?
What was the relationship between women’s suffrage and the abolitionist movement?
How is redistricting and gerrymandering related to the equal protection clauses?
What is the relationship between Roe v. Wade (1973) and privacy?
Why are civil liberties and safety often in tension with one another?
How often does the Supreme Court overturn decisions made by the appellate courts?

Answer:     the interval on which the curve is concave up is  (-∞, -1/2)======    we find the interval where this curve is concave up by finding the interval in which the 2nd derivative is positive.differentiate the curve equation with respect to x    let the function f denote be the anti-derivative of the inside expression, i.e. a function such that .then use the fundamental theorem of calculus:     differentiate again to get second derivative. we can use chain rule with 1/x as the outside function and 1 + x + x² as the inside function    find critical numbers of the second derivative. these numbers are where the 2nd deriv. is undefined or zero.where the 2nd derivative is zero: set (d²y/dx²) to equal 0 and solve for x    where the 2nd derivative is undefined: if the denominator is equal to zero, the derivative will be undefeined. attempting to solve the equation    1 + x + x² = 0results in a discriminant of      meaning that the equal 1 + x + x² = 0 has no real solutions and therefore will never equal zero.======our only critical number is x = -1/2.this forms two intervals to test the sign for: (-∞, -1/2) and (-1/2, ∞)test values into the 2nd derivative for (-∞, -1/2)if we try x = -1, we get      so the since the 2nd derivative of the curve is positive on the interval  (-∞, -1/2), the curve is concave up on (-∞, -1/2)test values into the 2nd derivative for (-1/2, ∞)if we try x = 0, we get      so the since the 2nd derivative of the curve is positive on the interval  (-∞, -1/2), the  curve is concave down on (-∞, -1/2).the interval on which the curve is concave up is  (-∞, -1/2)