Advanced Placement (AP), 05.05.2020 13:27, deadpoolcorvettehats

1.Explain what you think this quote means?

“Find a job you enjoy doing, and you will never have to work a day in your life.”

― Mark Twain

Answers: 3

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answered: andybiersack154

If you enjoy what you're doing then you will be happy and it won't feel like a job at all.

Explanation:

This is just my interpretation. You could honestly ask 1000 people and get 1000 different responses.

But. In my view he is telling you that if you're happy with what you are doing then it won't feel like a job at all. It will be something that you can do with joy.

answered: Guest

Iwould suggest the myers-briggs type indicator because the railroad unions are looking for which are focused introverts. the mbti was designed to provide a lot of information about what a person likes and what their personality based on the four-dimension scale. also for an employer it has been extremely to predict how an employee would act in a professional setting. this is what the railroad unions are looking for. they want the railroad workers to be focused and skillful to ensure the safety of everyone around them. but the other assessments don't match the criteria for the unions. like the measure disorder, emotions and self-esteem while the rorschach and tat tests are both projective tests that mainly measure someone’s personality. also, because this job is not easy, it is vital to make sure the employers are hiring the right people for the job.

answered: Guest

You need to figure out at which x-value does the graph has a tangent line slope of -1.remember, the derivative is the slope of the tangent line. so find the derivative function and set it to equal -1 to find the x-value that will have a tangent line slope of 0.differentiate with the chain rule. $\begin{aligned} f(x) & = (0.5)^{2x} \\ f'(x) & = 0.5^{2x} \cdot \ln(0.5) \cdot (2x)' \\ f'(x) & = 0.5^{2x} \cdot \ln(0.5) \cdot 2 \\ f'(x) & = 2\ln(0.5) \cdot 0.5^{2x} \end{aligned}$ set the derivative to equal -1 and solve for x. $\begin{aligned} -1 & = 2\ln(0.5) \cdot 0.5^{2x} \\ -\frac{1}{2} & = \ln(0.5) \cdot 0.5^{2x} \\ -\frac{1}{2\ln(0.5)} & = 0.5^{2x} \end{aligned}$ take log base 10 of both sides. also recall that $\log_c(m^n) = n \log_c m$ . $\begin{aligned} \log\left[ -\frac{1}{2\ln(0.5)}\right] & = \log\left[0.5^{2x}\right] \\ \log\left[ -\frac{1}{2\ln(0.5)}\right] & = 2x \log(0.5) \\ \dfrac{\log\left[ -\frac{1}{2\ln(0.5)}\right]}{2\log(0.5)} & = x \\ x & \approx 0.2356 \end{aligned}$ so the x-coord of the point of tangency is $x \approx 0.2356$ .the y-coordinate of this point of tangency can be calculated using the original function: $\begin{aligned} f(x) & = (0.5)^{2x} \\ f(0.2356) & = (0.5)^{2 \cdot 0.2356} \\ & \approx 0.7213 \end{aligned}$ using point-slope form, the equation of the tangent line is $y - 0.7213 = -1(x-0.2356)$ the x-intercept of this tangent line is when the graph is at y=0. $\begin{aligned} 0 - 0.7213 & = -1(x-0.2356)\\ - 0.7213 & = -(x-0.2356) \\ 0.7213 & = x-0.2356\\ x & = 0.9569 \end{aligned}$ this rounds off to $x & = 0.957$ .choice c.